By Dr Antonio Gulli

Bits is the second one of a chain of 25 Chapters dedicated to algorithms, challenge fixing, and C++ programming. This e-book is ready low point bit programming

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**Additional info for A Collection of Bit Programming Interview Questions solved in C++**

**Example text**

Print the binary representation of an unsigned int Solution Code 3. Compute whether or not an unsigned number is a power of two Solution Code 4. Set the i-th bit Solution 5. Unset the i-th bit Solution 6. Toggle the i-th bit Solution 7. Given an unsigned number with only one bit set, find the position of this bit Solution Code Solution Code Solution Code 8. Count the number of bits set in an unsigned number Solution Code Solution for sparse bitmaps Code Solution for dense bitmaps Code Solution for 32bit integers Code 9.

Solution Those patterns are named Gray code after the inventor Frank Gray[1]. It is convenient to generate them incrementally asIf we analyze the pattern, we understand that any list is generated from the previous list in three steps. At the beginning each element in is prepended by a 0. Then the list is reversed and each element is prepended by a 1. As final step the two intermediate lists are juxtaposed to create the new list. This process is repeated until we generate. size(); i++) std::cout << gray[i] << std::endl; } 25.

Unset the i-th bit Solution For a given number n we can unset the i-th bit with the expression 6. Toggle the i-th bit Solution For a given number n we can toggle the i-th bit with the expression 7. Given an unsigned number with only one bit set, find the position of this bit Solution If there is only one bit set, then the number must be a power of two. For identifying the position set we can AND the number with an appropriate bitmask. (i & n)) { i = i << 1; ++pos; } return pos; } Solution Another solution is using the logarithm for returning the position of the only bit set in the given unsigned .